Question

(a^2+b^2+c^2-ab-bc-ca) what's the formula of this ?​

Answer 1

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(a^2+b^2+c^2-ab-bc-ca) what's the formula of this ?

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$formula =$

${a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca$

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Answer 2

Answer:

This is a standard identity

$a^2+b^2+c^2 -ab-bc-ca$

Multiplying and diving by 2

$\frac{1} {2} \times 2a^2+2b^2+2c^2 -2ab-2bc-2ca$

$= \frac{1} {2} \times (a^2+b^2-2ab) + (b^2+c^2-2bc) + (c^2+a^2-2ac)\\= \frac{1} {2} [ (a-b)^2 + (b-c)^2 + (c-a)^2 ]$

Hope that helps

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