Question

(a^2+b^2+c^2+d^2)^2+(4abcd)^2​

Answer 1

Answer:

this is the ans

Step-by-step explanation:

Given : (a²−b²)(c²−d²)−4abcd

=a²c²−a²d²−b²c²+b²d²−2abcd−2abcd

=a²c²+b²d²−2abcd−a²d²+b²c²−2abcd

=(ac−bd)²−(ad−bc)²

=(ac−bd−ad+bc)(ac−bd+ad−bc) ....Since [p²−q²=(p−q)(p+q)]