Question

A^2-b^2-c^2+d^2-2(ad-bc)

Answer 1

Answer:

Please specify on the method.

Step-by-step explanation:

But according to my knowledge,

Solution:

a²-b²-c²+d²-2(ad-bc)

=a²-b²-c²+d²-2ad+2bc

=a²+d²-2ad-b²-c²+2bc

=(a²+d²-2ad)-(b²+c²-2bc)

=(a-d)²-(b+c)²

=[(a-d)+(b+c)][(a-d)-(b+c)]

=(a-d+b+c)(a-d-b-c)

Or

=(a+b+c-d)(a-b-c-d)

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Answer 2

Answer:

(a - d)^2 - (b + c)^2

or

(a - d + b + c)(a - d - b - c)

Step-by-step explanation:

a^2 - b^2 - c^2 + d^2 -2(ad - bc)

a^2 - b^2 - c^2 + d^2 -2ad - 2bc

(a^2 + d^2 - 2ad) + (-b^2 - c^2 - 2bc)

(a^2 + d^2 - 2ad) - (b^2 + c^2 + bc)

(a - d)^2 - (b + c)^2

(a - d +b + c)(a - d - b -c)