Question

(a^2-b^2)(c^2-d^2)-4abcd

Answer 1

Hi there,

Solution:-
(a^2-b^2)(c^2-d^2)-4abcd
a²c²-a²d²-b²c²+b²d²-4abcd
a²c²-a²d²-b²c²+b²d²-2abcd-2abcd
a²c²+b²d²-2abcd-a²d²-b²c²-2abcd
(a²c²+b²d²-2abcd)-(a²d²+b²c²+2abcd)
[(ac)²+(bd)²-2abcd]-[(ad)²+(bc)²+2abcd]

We know that,
[x²+y²-2xy=(x-y)²] and
[x²+y²+2xy=(x+y)²]

=>(ac−bd)²−(ad+bc)²

We know that,
[(a²-b²)=(a+b)(a-b)]

=>[ac-bd+(ad+bc)][ac−bd)−(ad+bc)]

=>(ac-bd+ad+ac)(ac-bd-ad-bc) ANSWER...

Hope this helps you:-)))

Answer 2

here is the answer
(a^2-b^2)(c^2-d^2)-4abcd
(a^2×c^2)-(d^2×a^2)-(b^2×c^2)+(d^2×b^2)-4abcd

(ac-da)(ac+da)-(db+bc)(db-bc)-4abcd
..................... ............ ..... ... . ...
from this u Will get the answer