A^2+b^2=c^2 find the value of (a^6+b^6-c^6)÷a^2b^2c^2
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helo guys its your answer
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math]a^2+b^2=-c^2[/math] [math](a^2+b^2)^3 =-c^6[/math] ... [math]a^6+b^6+c^6+3×a^2b^2( -c^2)=0[/math] [math]Or, ... If a^3 + 3a^2 + 9a = 1, then what is the value of a^3 + (3/a)?.
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