Question

(a)2+(b)2=(c)2 then loga(c-b) +loga(c+b)=​

Answer 1

Step-by-step explanation:

$log_{a}(c - b) + log_{a}(c + b) \\ = log_{a}( {c}^{2} - {b }^{2} )...(1) \\ {a}^{2} + {b}^{2} = {c }^{2} \\ = > {a}^{2} = {c}^{2} - {b}^{2} .. ..(2) \\ using \: (1) \: and \: (2) \\ = log_{a}( {a}^{2} ) \\ = 2log_{a}(a) \\ = 2 \times 1 \\ = 2$

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