Math, asked by sonumangotra7238, 4 months ago

A^2+b^2+c^2=? when a+b+c=17

Answers

Answered by RehanAk73

0

Answer:

a^2+b^2+c^2=289

Step-by-step explanation: a+b+c=17 (GIVEN)

a^2+b^2+c^2=289 squaring on both sides

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