Question

a^2+b^2 when a+b=4and an=3

Answer 1

Answer:

$a + b = 4 \\ squaring \: both \: sides \\ {(a + b)}^{2} = {4}^{2} \\ {a}^{2} + 2ab + {b}^{2} = 16 \\ given \: ab = 3 \\ {a}^{2} + {b}^{2} + 2(3) = 16 \\ {a }^{2} + {b }^{2} + 6 = 16 \\ {a}^{2} + {b}^{2} = 16 - 6 \\ = 10$