Question

(a^2 * b^2 * x^2) + (b^2 * x) - (a^2 * x - 1) = 0

To find, x

Answer 1

Answer:

 x = 1/b^2

Step-by-step explanation:

Okay so,

= $a^{2}b^{2}c^{2} +b^{2}*x-a^{2}*(x-1)= 0$

= $a^{2} b^{2} x^{2} +b^{2}x-a^{2}x-a=0$

= Take common b^2x

=$b^{2}x(ax^{2}+1) -1(ax^{2} -1)$

= $(ax^{2} +1) (bx^{2} -1)=0$

= ax^2  +1=0                or             bx^2-1=0

   x=$\frac{-1}{a^{2} }$                          or              x = 1/b^2

=   hence ,   x cant be -1/a^2

 =   x = 1/b^2