(a/2+b/3+c/4)² solve using identity
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Using the formula: (x+y+z)²=x²+y²+z²+2xy+2yz+2zx.
so, (a/2+b/3+c/4)²= (a/2)² + (b/3)² + (c/4)² + 2(a/2)(b/3) + 2(b/3)(c/4) + 2(c/4)(a/2).
=> a²/4 + b²/9 + c²/16 + ab/3 + bc/6 + ac/6.
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Hope it helps
Thank you guys
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