a + 2 b + 3 c whole square expand it
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Answered by
1
Step-by-step explanation:
(a+2b+3c)^2
=(a+2b+3c)(a+2b+3c)
=a(a+2b+3c)+2b(a+2b+3c)+3c(a+2b+3c)
=a^2+2ab+3ac+2ab+4b^2+6bc+3ac+6bc+9c^2
=a^2+4b^2+9c^2+4ab+12bc+6ac
Answered by
1
(a+2b+3c)^2
a^2 + 4b^2 + 9c^2 +
2.[ (a)(2b) + (2b)(3c) + (3c)(a) ]
a^2 + 4b^2 + 9c^2 + 4ab + 12bc + 6ca
a^2 + 4b^2 + 9c^2 +
2.[ (a)(2b) + (2b)(3c) + (3c)(a) ]
a^2 + 4b^2 + 9c^2 + 4ab + 12bc + 6ca
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