Question

A=-2,b=-3
subtract a^2-2ax+x^2 from the sum of 3a^2-5ax-x^2and -2a^2 +3ax+4x^2.​

Answer 1

Answer:

2x² is the answer

Step-by-step explanation:

3a²-5ax-x² + (-2a² +3ax+4x²)

3a²-5ax-x² -2a² +3ax+4x²

put a = -2

3(-2)² - 5(-2)x - x² - 2(-2)² + 3(-2)x + 4x²

3(4) - (-10x) - x² - 2(4) + (-6x) + 4x²

12 + 10x - x² - 8 - 6x + 4x²

3x² + 4x + 4

a² - 2ax + x²

put a = -2

(-2)² - 2(-2)x + x²

4 - (-4x) + x²

x² + 4x + 4

Now Subtract x² + 4x + 4  from 3x² + 4x + 4

3x² + 4x + 4 - (x² + 4x + 4 )

3x² + 4x + 4 - x² - 4x - 4

2x²          (4x - 4x = 0; 4 - 4 = 0)

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