Question

A + 2 b + 36 gives a b to c three reaction of 6 gram of a 6 into 10 raise to power 23 atom of b and 0.036 mole of c = 4.8 gram of compound ab2 c3

Answer 1

Answer:

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Explanation:

Atomic mass of A = 60 g/mol

Atomic mass of A = 60 g/molAtomic mass of B = x g/mol

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/mol

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 mol

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol6\times 10^{23} atoms of B

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol6\times 10^{23} atoms of B1 mol=6.022\times 10^{23}\approx 6\times 10^{23} atoms

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol6\times 10^{23} atoms of B1 mol=6.022\times 10^{23}\approx 6\times 10^{23} atoms Moles of B = 1 mol Hope this would be helpful to you.

Answer 2

Answer:

Refer to the attachment