Math, asked by anjanajaiswal761, 9 months ago

a:2=b:5=c:8 then 50% of a = 20% of b = x % of c. find x

Answers

Answered by veerendrakumaruppu
15
a:2 = b:5 = c:8

a:2 = b:5

5a = 2b

a = 2b/5 —-> 1

b = 5a/2 —-> 2

b:5 = c:8

8b = 5c

b = 5c/8 —-> 3

c = 8b/c —-> 4

20% of b = x% of c

(20/100)*b = (x/100)*c

(20/100)*(5c/8) = (x/100)*c [from 3]

20*5/8 = x

x = 12.5 ——> Answer

Answered by siddhikahemang2005
0

a:2 = b:5 = c:8

a:2 = b:5

5a = 2b

a = 2b/5 —-> 1

b = 5a/2 —-> 2

b:5 = c:8

8b = 5c

b = 5c/8 —-> 3

c = 8b/c —-> 4

20% of b = x% of c

(20/100)*b = (x/100)*c

(20/100)*(5c/8) = (x/100)*c [from 3]

20*5/8 = x

x = 12.5 ——> Answer

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