Question

a^2+(b+ac)x+bc by x+c

Answer 1

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Answer....

Solution :

We have
${a}^{2} + (b + ac)x + bc \\ \\ = ({ax}^{2} + bx) + (acx + bc) \\ \\ = \: x(ax + b) + c(ax + b) = (ax + b) (x + c)\\ \\ = ( {ax}^{2} + (b + ac)x + bc) \div (x + c) \\ \\ = \frac{ {ax}^{2} + (b + ac)x + bc}{x + c} \\ \\ = \frac{(ax + b)(x + c)}{(x + c)}$
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Answer 2

ax^2+(b+ac) x+bc by x+c =ax^2+acx +bx+bc by x+c =ax (x+c)+b(x+c)by (x+c)=(ax+b) (x+c)by (x+c)=ax+b