a^2(b+c)-(b+c)^3 factorize it
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Answer :
Now, a² (b + c) - (b + c)³
= (b + c) {a² - (b + c)²}
= (b + c) (a + b + c) (a - b - c),
[using the identity x² - y² = (x + y) (x - y)]
which is the required factorization.
#MarkAsBrainliest
Now, a² (b + c) - (b + c)³
= (b + c) {a² - (b + c)²}
= (b + c) (a + b + c) (a - b - c),
[using the identity x² - y² = (x + y) (x - y)]
which is the required factorization.
#MarkAsBrainliest
Answered by
2
Heya !!!
A² ( B + C ) - ( B + C )³
=> A² ( B + C ) - ( B+ C × B + C × B + C )
=> B + C ( A²- ( B + C × B + C)
=> B + C { ( A² - ( B + C )² }
=> B + C { ( A + B + C ) ( A - B - C ) }
=> ( B + C ) ( A + B +C ) ( A - B - C ).
HOPE IT WILL HELP YOU..... :-)
A² ( B + C ) - ( B + C )³
=> A² ( B + C ) - ( B+ C × B + C × B + C )
=> B + C ( A²- ( B + C × B + C)
=> B + C { ( A² - ( B + C )² }
=> B + C { ( A + B + C ) ( A - B - C ) }
=> ( B + C ) ( A + B +C ) ( A - B - C ).
HOPE IT WILL HELP YOU..... :-)
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