a^2+b2=7ab prove that 2log(a+b)=2log3+loga+logb
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Hi ,
a² + b² = 7ab
=> a² + b² + 2ab = 7ab + 2ab
=> ( a + b )² = 9ab
=> ( a + b )² = 3²ab
=> log( a + b )² = log ( 3²ab )
=> 2log( a + b ) = log 3² + log a + log b
=> 2log(a+b) = 2log3 + log a + log b
Hence proved.
I hope this helps you.
: )
a² + b² = 7ab
=> a² + b² + 2ab = 7ab + 2ab
=> ( a + b )² = 9ab
=> ( a + b )² = 3²ab
=> log( a + b )² = log ( 3²ab )
=> 2log( a + b ) = log 3² + log a + log b
=> 2log(a+b) = 2log3 + log a + log b
Hence proved.
I hope this helps you.
: )
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