a*2+bc+ab+ac factorize
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a² h ya a×2 h ??
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a+ bc +ab + aC
Rearranging the terms, we get
=a+ ab +ac + bc
= (axa + axb +( axc+bxc)
Take a and c common in
first and second brackets5
respectively, we get
a( a + b) + c( a + b)
Again take (a +b)
Common, we get
= (a +b ) a +c)
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