a^2/bc +b^/ca +c^2/ab=3 prove that
hetav74:
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we know that if, a+b+c=0
then,
a³+b³+c³ = 3abc
(a³+b³+c³)/abc = 3
a³/abc + b³/abc + c³/abc = 3
a²/bc + b²/ac + c²/ab = 3 (PROVED)
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