Question

A 2 cm long object is placed perpendicular to the principal axis of a concave mirror. The distance of the object from the mirror is 30 cm and it's image is formed at 60cm from the mirror on the same said of the mirror as the mirror on the same side of the mirror as the object. Find the height of the image formed​

Answer 1

Answer:

Distance of object from the mirror, u=−30

Distance of image from the mirror, v=−60 , image is real.

Now we know magnification ratio m=−

u

v

m=−

−30

−60

m=−2

Height of object h=2cm

Image height h

1

=m×h=−2×2=−4cm

Height of image is 4 cm and its inverted.