Question

A 2 cm tall object is placed 40 cm from a diverging lens of focal length 15 cm find position and size of omage

Answer 1

Answer:

Please mark it as brainlist Please .......

Step-by-step explanation:

I hope it may help you

Answer 2

Answer:

Step-by-step explanation:

h1 = 2 cm

u = -40 cm

f = -15 cm

1/v – 1/u = 1/f

1/v – 1/-40 = 1/-15

1/v = - (1/15) – 1/40

1/v = -11/120

V = -10.90 cm  

m = v/u = h2/h1

-10.90/-40 = h2/2

h2 = 0.54 cm