Question

A 2 cm tall object is placed perpandicular to the principal axis of a convex lens of focal
length 10 cm The distance of the object from the lens is 15 cm Find the nature, Position
and size of the image.


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Answer 1

Answer:

Explanation:

Given: Height of object Hy = +2.4 cm

Focal length of convex lens = +18 cm (for convex lens)

Object distance u = -12 cm

Applying the lens formula:

1/v - 1/u = 1/f

1/v - 1/-12 =1/18

1/v = 1/18 -1/12

On calculating we get

1/v = 1/36

Therefore, v= -36 cm

Magnification is given by the relation:

m = v/u

m = 36/-12 =3

Also magnification is given by:

m=h2/h1

3=h2/2.4

Therefore, height of image will be 7.2 cm

The image formed will be virtual and erect.