Question

a=-2,d=0 in arithmetic progressin.​

Answer 1

Answer:

Given that first term of an AP

that is a is equals to - 2 and

common difference of that AP that is D is equals to zero.

so,

$a_1 = - 2 \\ a_2 = - 2 + 0 = - 2 \\a_3 = - 2 + 2(0) = - 2 \\ a_4 = - 2 + 3(0) = - 2 \\ a_5 = - 2 + 4(0) = - 2 \\ . \\ . \\ . \\ . \\ . \\ . \\ . \\ . \\ a_n = - 2 + n(0) = - 2$

It concludes that the AP whose common difference is zero is a constant progression

whose all terms are equals to its first term.

So, the AP which has first term = -2 and common difference = 0 is

-2,-2,-2,-2,-2,-2,-2,-2.........