Question

A 2-digit number becomes four-sevenths of itself when the positions of its digits a
inter-changed. The difference between both digits is 3. What is the number​

Answer 1

Answer:

Step-by-step explanation:

Let the unit place be = y

Let the tens place be = x

original number = 10x + y

reversing number = 10y + x

Conditions = 1

=> A two digit number becomes four seventh

of itself when the position of it's digit is

interchanging

=> 10y + x = 4/7 ( 10x + y)

=> 7 ( 10y + x) = 4 ( 10x + y)

=> 70y + 7x = 40x + 4y

=> 66y = 33x

=> 2y = x ........(1)

Conditions = 2

The difference between the both digit

is = 3

=> x - y = 3 .......(2)

From equation (1) and (2) we get,

put the value of equation (1) in equation (2)

we get,

=> 2y - y = 3

=> y = 3

Put the value of y = 3 in equation (1)

we get,

=> x = 2(3)

=> x = 6

Therefore,

The number are = 10x + y

=> 10(6) + 3 = 63

The number is = 63

hope this helped