Question

A 2-digit number is 10 times the sum of its digits.the tens digit is 2 greater than the units digit. find the number​

Answer 1

Step-by-step explanation:

hi, Mr.

this is solution

Answer 2

Answer:

Let n(a,b) be two digit number.

n(a,b)=10a+b

Units digit=ten's digit+2

b=a+2

$$\text{number \times sum of digits}=144$$

(10a+b)(a+b)=144

(11a+2)(2a+2)=144 (∵b=a+2)

11a^{2}+13a+2=72$$

11a

2

+13a−70=0

11a

2

+35a−22a−70=0

(11a+35)(a−2)=0

∴a=2,b=4

∴24 is the required number.