a 2 digit number is 4 more than 6 time the sum of its digits if 18 is added to the number the digits are reversed find the digits
Answers
Answer:
Given, two - digit number is 4 more than 6 times the sum of its digits. ⇒ 10b + a = 6(a + b) + 4 ⇒ 4b = 5a + 4 ------- (1) Also, if 18 is subtracted from the number, the digits are reversed. ⇒ 10b + a – 18 = 10a + b ⇒ b – a = 2 ------- (2) Multiplying eq2by 4 and subtracting from eq1 ⇒ 4b – 5a – 4b + 4a = 4 – 8 ⇒ a = 4 Thus, b = 6 Number is 64Read more on Sarthaks.com - https://www.sarthaks.com/1076335/digit-number-more-than-times-digits-subtracted-from-number-the-digits-reversed-find-number
Step-by-step explanation:
Given, two - digit number is 4 more than 6 times the sum of its digits. ⇒ 10b + a = 6(a + b) + 4 ⇒ 4b = 5a + 4 ------- (1) Also, if 18 is subtracted from the number, the digits are reversed. ⇒ 10b + a – 18 = 10a + b ⇒ b – a = 2 ------- (2) Multiplying eq2by 4 and subtracting from eq1 ⇒ 4b – 5a – 4b + 4a = 4 – 8 ⇒ a = 4 Thus, b = 6 Number is 64Read more on Sarthaks.com - https://www.sarthaks.com/1076335/digit-number-more-than-times-digits-subtracted-from-number-the-digits-reversed-find-number
Answer:
Let the number be 10 x + y . It is also given that if 18 is subtracted from the number the digits gets reversed. The original number is 10 ( 6 ) + 4 = 60 + 4 = 64 . Therefore, the number is 64.