Question

A 2 digit number is 4 times the sum and twice the product of its digits find the number

Answer 1

Answer:Sol: let the digits be x and y

let x is in the tens place then

it sill become 10x let y is in once place the it will become

1y

the original number be 10x+y

from the question

10x+y=4(x+y)

10x+y=4x+4y

10x-4x+y-4y=0

6x-3y=0

2x-y=0

2x=y. eq-1

again according to question

10x+y=2(xy)

substitute y=2x

10x+2x=2x(2x)

12x/2x=2x

6=2x

x=3

if x=3 then y=?

2x=y

y=6

the number is 36

Answer 2

Answer:

l

Step-by-step explanation:

let digit be x, y

x is ten's place digit = 10x

y is ones place digit =1y

original number be 10x+y

from given condition

10x+y =4(x+y)

10x+y=4x+4y

6x-3y=0

3x-2y =0

2x-y=0

2x=y...(1)

According to the given condition

10x+y =2(xy)

put y=2x

10x+2x=2x(2x)

12x/2x=2x

6=2x

x=3

put x=3 in equation 1

2x=y

y=6

and number is

10x+y

10(3)+6

30+6

36

please fallow me