A 2 digit number is 6 more than 4 times the sum of its digit. If 27 is added to the number, its digits are reversed. Find the number
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Answer:
Step-by-step explanation:
Let the two digit number be 10x + y.
According to question, 10x+y+27=10y+x(no.formed by reversing its digits)
10x+y-10y-x+27=0
9x-9y+27=0
x-y+3=0(divide the equation with 9)..........(1)
4(x+y)+6=10x+y
4x+4y-10x-y+6=0
-6x+3y+6=0
2x-y-2=0...........(2)
Solve 1 and 2
x-2x+3+2=0
x=5
Now in (1)
5-y+3=0
y=8
The two digit number is 58.
Hope it helps you.
Answered by
1
Answer:
ye to mera bhi question hi
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