A 2-digit number is formed by either subtracting 16 from eight times the sum of the digits or by adding 24 to 20 times the difference of the digits. The digit at tens place is greater than the digit at units place. Find the number.
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Answer:
Let’s say x is the unit digit and y is the tenth digit.
y+x = 9 -> y=9-x
10x+y = 10y+x+27
10x+9-x = 10(9-x)+x+27
10x+9-x = 90–10x+x+27
18x = 108
x = 6
so y = 3
let’s check
63 - 36 =27
27 = 27 (correct)
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