Question

A 2-digit number is such that ones digit is 1 more than the tens digit. The ratio of this number and the
number formed by reversing its digits is 5:6. Find the number.

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Answer 1

$GOOD \: \: MORNING \: \: \: \\ \\ let \: the \: digits \: of \: that \: two \: digit \: number \\ be = xy \\ while \: x \: is \: at \: tens \: place \: and \: y \: is \: at \: \\ ones \: place \\ \\ \\ ACCORDING \: to \: the \: Given \: \: Question \: \: \\ \\ y = x + 1 \: \: \: \: ... \: \: Equation \: \: i \\ \\ \frac{10x + y}{10y + x} = \frac{5}{6} \\ \\ 60x + 6y = 50y + 5x \\ \\ 60x - 5x = 50y - 6y \\ \\ 55x - 44y = 0 \: \: \: \: ....Equation \: \: \: ...ii \\ \\ now \: put \: value \: of \: y \: in \: Equation \: \: \\ ii \: we \: have \\ \\ 55x - 44(x + 1) = 0 \\ \\ 55x - 44x - 44 = 0 \\ \\ 11x = 44 \\ \\ x = 4 \\ \\ put \: value \: of \: x \: in \: Equation \: i \: we \: have \\ \\ y = 4 + 1 \\ \\ y = 5 \\ \\ so \: the \: two \: digit \: number \: is \: 45$

Answer 2

Answer:

hey mate your answer

Step-by-step explanation:

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