Question

A 2 digit number is such that the
Product of its digits is 18 , when 63
is subtracted from the number the digits
interchange their places. find the number?​

Answer 1

Answer:

let the two digit number be 10x+ y

ATQ,. x × y= 18..........(1)

10x + y - 63 = 10 y + x

9x - 9y - 63= 0

9x - 9y = 63

x-y = 7..........(.2)

x= 7+y

put value of x in eq 1b, we get

( 7+y ). y = 18

y² + 7y = 18

y² +7y-18=0

y² +9y -2y -18= 0

y(y+9) -2 ( y +9) =0

( y+9) (y-2). = 0

y=-9 , y = 2

y= 2........

so, x= 7+2=9

therefore the two digit number is 10(9)+2

= 92.....

HOPE IT HELPS YOU

FALLOWE FOR HELP

JYOTIRMAY TRIPATHI

Answer 2

Step-by-step explanation:

hope it helps you mate....

pls mark it as the brainliest answer and give me a thanks....

pls rate my answer and please follow me....

thank you .....

have a bright future ahead....