A 2 digit number is such that the sum of its digits is 4. If 8 is added to the number , its digits are reversed . Find the number
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the number is 13
Given:- sum of the digits of two digit number=4
To find:- The number
Formula:- This can be solve using linear equations.
Solution:-
Let the tens digit be x and unit digit be y
So the number becomes 10x+y
Sum of digits = 4
x + y = 4
x=4-y....eq1
Now when 8 is added to number it becomes = 10x+y+8
Now digits are reversed of this new number
So new number is 10y+x
10y+x = 10x+y+8
10y+x -10x -y=8
9y-9x=8
now putting value of x from eq 1
9y - 9(4-y) = 8
9y - 36 + 9y = 8
18y = 8+36
18y = 44
y = 2.4 rounding off
y=3
x = 4 - y
x= 4 - 3
x=1
So the number becomes 13
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