Question

A 2 digit number is twice the sum of its digit . If 63 is added to it the digits are reversed . Find the number.​

Answer 1

Step-by-step explanation:

Open in App

Sign In

Quora uses cookies to improve your experience. Read More

A two digit number is six times of its sum. When it's sum is added to the number the resultant is 63. What is the number?

Ad by OPPO Mobile India

Is the OPPO F19 Pro+ 5G the best smartphone in its price range?

The OPPO F19 Pro+ 5G has quickly taken the smartphone industry by storm! This power-packed device is available for a compelling p

Continue reading

9 Answers

Profile photo for Sarthak Dash

Sarthak Dash, Founder at APTITUDE CLUB (2018-present)

Answered 3 years ago · Author has 529 answers and 1.9M answer views

Now there are two ways to do this.

Method 1:

Let the 2-digit number be xy.

Now xy can be expended as (10x + y).

10x + y = 6(x + y)

=> 4x - 5y = 0

Similarly, (x + y) + (10x + y) = 63

=> (11x + 2y) = 63

Now solving these two equations, x=5, y=4. So the number is 54.

Method 2:

The 2-digit number is a multiple of 6. And it can be concluded that it is less than 63.

So the first number that is a multiple of 6 and immediately less than 63 is 54. Just cross-check and Voila..

Answer 2

Answer:

The number is 18.

Step-by-step explanation:

Given:- The 2 digit number is twice the sum of its digit.

            When 63 is added to the number, digits are reversed.  

To Find:- Find the number.

Solution:-

Let the 2 digit number be ab.

a is at ten's place. So the number can be expressed as 10a + b.

Acc. to the question,

10a+b = 2( a + b )

⇒ 10a + b = 2a + 2b

⇒ 8a = b

When 63 is added then digits are reversed,

(10a+b) + 63 = 10b+a

⇒ 9b - 9a = 63

⇒ b - a = 7

Putting b = 8a in the above equation,

⇒ 8a - a = 7

⇒ 7a = 7

⇒ a = 1

Putting a = 1 in b - a = 7,

b = 7 + a

⇒ b = 7 + 1

⇒ b = 8

Therefore, the number is 18.

#SPJ2

https://brainly.in/question/49384397

https://brainly.in/question/1542570