Question

A 2F capacitor charged from 10 volts battery. What is the stored energy (in J)

in it ​

Answer 1

Answer:

PLEASE SEE THE ATTACHMENT....

@AMIMUL HOQUE

Answer 2

Answer :

Capacitance of capacitor = 2μF

Voltage of battery = 10 volts

We have to find energy stored in capacitor in μJ$.$

⧪ Energy stored in capacitor is given by

• E = 1/2 × CV²
• E = QV/2
• E = Q²/2C

We have given values of capacitance and voltage so we will use first formula.

⭆ E = 1/2 × CV²

⭆ E = 1/2 × 2 × (10)²

⭆ E = 200/2

⭆ E = 100 μJ

Cheers!