A 2 - gram object, located in a region of uniform electric field E = (300 NC) i charge O. The object released from rest at x = 0, has a kinetic energy of 0.12 Jatx=05 Then Qis (D)- 800 uc (A) 400 uc () (B) - 400 uc (C) 800 uc
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Answer:
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Explanation:
Correct option is
C
(4.5i^+6j^)m/s2
ATQ, Electric field, E=(3i+4j)N/c
mass =2mg=2×10−6kg
charge =3×10−6c
F=qE=(3i+4j){3×10−6}N
Also, from Newton's law, F=ma
or a=mF=2×10−6(3i+4j)(3×10−6){m/s2}
=(4.5i+6j)m/s2
∴ Option (C) is the correct answer.
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