Question

a=-2+iota b=-2-iota then a-b=
(iota+1)(iota-1)=
(3y-2)+iota(7+2x)=0 x=??
iota=√-1​

Answer 1

Answer:

a=-2+iota b=-2-iota then a-b=

(iota+1)(iota-1)=

(3y-2)+iota(7+2x)=0 x=??

iota=√-1

Answer 2

Answer:

|z| = |x + y = x² + y²

Open Answer in App 71

<br>

|x + iy| = |(2 + i)(2 + 2i)(2 + 3i)...( <br>

= |2i||2 + 2i||2+ 3i... 2+9i|

<br>

4+1· √√√2² +2²... √/2² +9²

1x² + y² = √√5. √√8. √13... √85 2

<br>

<br>

x² + y² = 5 · 8 · 13 · ... · 85 <br> option 1 is correct.