Question

A 2 kg ball is moving at a speed of 4 m/s toward a ball of the same mass at rest. They both stick together after the collision. What is the velocity of the two ball system and what type of collision is it?

Answer 1

Answer:

Using law of conservation of momentum-

m1u1 +m2u2=m1v1+m2v2

Given

m1=2 kg=m2

u1=0=u2

v1=4

v2=?

0+0=2×4+2× v2

v2=4 m/s

It is a type of positional collision

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