A 2 KG BALL IS THROWN UP WITH AN INITIAL VELOCITY OF 12M/S AND REACHES MAX HEIGHT OF 10 M . HOW MUCH ENERGY IS DISSIPATED BY AIR DRAG ACTING ON THE BALL DURING THE ASCENT?
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2 KG BALL IS THROWN UP WITH AN INITIAL VELOCITY OF 12M/S AND REACHES MAX HEIGHT OF 10 M . HOW MUCH ENERGY
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Answer:
2g = 20N
Explanation:
since acceleration is constant = g
and the ball comes to rest
therefore there is some force equal and opposite of the motion
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