Question

A 2 kg ball on a string is rotated about a circle of radius 10 m. The maximum tension allowed in the string is 50 N. What is the maximum speed of the ball ??

Answer 1

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$\implies$ The centripetal force in this case is provided entirely by the tension in the string.

If the maximum value of the tension is 50 N,

★radius is set at 10 m

Put in equation for centripetal force:

$t = fc$
$\implies$=mv²/r = √10×50 /2

$\implies$ 15.8m/sec

Answer 2

Hola mate
The answer of ur question is here



Question
A 2 kg ball on a string is rotated about a circle of radius 10 m. The maximum tension allowed in the string is 50 N. What is the maximum speed of the ball ??



Answer
Mass of the ball = 2kg
Radius of circle = 10 m

Tension which is maximum = 50 Newton




So f=mv2/r



50=2v2/10

from which we get

v=√250
Maximum speed of the ball =15.81m/sec




hope it helps