Question

A 2-kg block is attached to a horizontal ideal spring with a spring constant of 200 N/m. When the spring has its equilibrium length the block is given a speed of 5 m/s. What is the maximum elongation of the spring

Answer 1

Explanation:

pressure = 200 N/m^2

mass= 2 kg

speed = 5 m/s

as we know ,

2gh=v^2-u^2

2×9.8×h=5^2-0

2×9.8h=25

h =25 ×10/2×9.8

=125/98

=1.27meter