Question

A 2 kg block is placed over a 4 kg block and both are placed on a smooth horizontal surface. The coefficient of friction between between the blocks is 0.20.Find the acceleration of the two blocks if a horizontal surface of 12 N is applied to (a) the upper block , (b) the lower block. Take g = 10 m/s2.​

Answer 1

Answer:

Given,

masses=2kg,4kg

Coefficient 0.20

Force =12N

R

1

−2g=0

R

1

=2x10=20

2a+0.2R

1

−12=0

2a+0.2(20)=12

2a=12−4

a=4m/.s

2

Again,

4a−μR

1

=0.2(20)=4

a

1

=1m/s

2

2kg block has acceleration 4m/s

2

and that of 4kg is 1m/s

2