Math, asked by varunrangaraaj0102, 5 months ago

A 2 kg block is resting on a rough horizontal surface, the frictional force acting on the
block is (coefficent of friction between the block and the surface is 0.2)
(A) zero
(B) 3.92 N
(C) 19.6 N
(D) none of these​

Answers

Answered by Sanskarbro2211
1

Given:-

M = 2 Kg

μ = 0.2

We know that:-

g = 9.8 \frac{m}{s^{2} }

f = μN

N=mg

From above information:-

f = 0.2 * 2 * 9.8 N

 = 3.92 N

This is option (B) 3.92 N .

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