A 2 kg block is resting on a rough horizontal surface, the frictional force acting on the
block is (coefficent of friction between the block and the surface is 0.2)
(A) zero
(B) 3.92 N
(C) 19.6 N
(D) none of these
Answers
Answered by
1
Given:-
M = 2 Kg
μ = 0.2
We know that:-
f = μN
N=mg
From above information:-
f = 0.2 * 2 * 9.8 N
= 3.92 N
This is option (B) 3.92 N .
Similar questions