A 2 kg body is sliding up an inclined plane of inclination 30°. Find the work done by the force of gravity in moving the body through 1 m.
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Work done is given by the formula:
W=Fdcos(90−θ)
As the angle between force and direction of displacement=90−θ
Therefore W=mg×d sinθ=mg×d sin300=2×10×1×12=10J
W=Fdcos(90−θ)
As the angle between force and direction of displacement=90−θ
Therefore W=mg×d sinθ=mg×d sin300=2×10×1×12=10J
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