Physics, asked by RAJASHREEDAS, 8 months ago

A 2 kg mass tied with a weightless string that passes over a smooth Pulley is being pulled due to the vertical fall of a 3 kg mass tied to the other end of the string. The string snapped 5 second after the fall started what further distance does the 2 kg mass rise through?​

Answers

Answered by mahhi1096drc
1

Answer:

A block of mass 2 kg is tied at one end of a light inextensible string. At the other end of the string another book of mass 1 kg is tied. Initially the block of mass 1 kg is tied. Initially the block of mass 1 kg is on the ground and the system of these blocks in stationary as shown in figure. Now the masses are released. Find the common velocity of the blocks when the mass of 2 kg touches the ground. The pulley is smooth and weightless. The initial height of block of 2 kg from the ground is 3 m. (g = 9.8 m/s²)

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Answered by Medhalakshmi
4

Explanation:

Consider the acceleration of masses be indentical. Then calculate it's value and at the end, calculate the distance considering that the masses are initially at rest.

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