a 2 kg shot is fire from a cannon of mass 198 kg with a velocity 50m/s wrt the gun the the velocity of the recoil of the gun is brainly
sainivetha:
my ans
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Answered by
12
m1 =198kg
v1=?
m2=2kg
v2=?
according linear momentum
m1v1=m2v2
198v1=2*50
v1=100/198
v1=?
m2=2kg
v2=?
according linear momentum
m1v1=m2v2
198v1=2*50
v1=100/198
Answered by
5
"In the question, are given the masses of both the cannon and the shot and the velocity of the shot.
We have to find the recoil velocity of the cannon.
We can find it using the law of conservation of momentum.
Initial momentum of the system = 0
Final momentum of the system = m1v1 + m2v2
m1v1 + m2v2 = 0
2*50 = 198*v2
v2 = 100/198 m/s
"
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