A 2 kg stone attached to a string is whirled in a
horizontal circle of radius 0.5 m. The string makes an
angle of 30° with the vertical. The resultant force on
the stone due to tension and weight is
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The resultant force on the stone due to tension and weight is 8 N
Explanation:
- Let the tension in the string be = T ( N )
- The value of tension T in vertical direction is:
- T cos θ = m g
The centripetal force in the circle will be provided by T sinθ
T sin θ = mv^2 / r
[Since sin θ = 1/2]
T x 1/2 = 2 x 1^2 / 0.5
T = 2 x 2 / 0.5
T = 4 / 0.5 = 8 N
Thus the resultant force on the stone due to tension and weight is 8 N
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