A 2 m crowbar is employed to lift a load of
300 kg. What force must be applied to one end
of the crowbar when a stump acting as a
fulcrum is placed under the crowbar 0.5 m
away from the end on which the load rests?
Neglect the weight of the crowbar.
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Answer:
1000N
Explanation:
Clockwise moment of force = anticlockwise moment of force
Moment = Force in Newtons X distance to fulcrum
Load of 300kg = 3000N
Distance of load from fulcrum 0.5m
Force applied has to be found call this F
Distance of applied force to the fulcrum is 1.5 m (2 m - 0.5)
3000 x 0.5 = F x 1.5
F = 3000 x 0.5 /1.5
F = 1000 N (or 100 kg although kg is not force)
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