Question

A 2 m long rod of radius 1 cm which is fixed from one end is
given a twist of 0.8 radius. The shear strain developed will be
(a) 0.002
(b) 0.004
(c) 0.008
(d) 0.016​

Answer 1

Answer:

(D) 0.016 is right answer

Answer 2

The shear strain developed will be 0.004 radian.

Explanation:

It is given that,

Length of the rod, l = 2 m

Radius of the rod, r = 1 cm = 0.01 m

Twisty angle, $\theta=0.8\ radian$

We need to find the shear strain developed. It is given by :

$\phi=\dfrac{r\theta}{l}$

$\phi=\dfrac{0.01\times 0.8}{2}$

$\phi=0.004\ radian$

So, the shear strain developed will be 0.004 radian. Hence, this is the required solution.

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