Question

a 2 MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T. the force on proton is ​

Answer 1

Explanation:

some are not captured in the picture

shortly, we know force on a charge when the charge is in magnetic field is F=q v B

have their usual meaning.

but the problem is the energy of proton is given

so, from this we need to calculate the velocity

the rule is E=P^2/2m

where m is the mass of proton=1.6×10^(-19)

• Finally, F= q (2E/m)^1/2 B
• F=4.3×10^-4