Question

A 2 mh a 3.3 mh and a 0.2 mh inductor are connected in series. the total inductance is

Answer 1

Given:

2 mH,  3.3 mH and a 0.2 mh inductor

Find total inductance =?

• It is given that the all inductor connected in series
• So find the value of total inductance add the value of all inductor connected in series
• Values are 2, 3.3, 0.2
• Here the calculation are:
• 2 + 3.3 + 0.2=5.5

Hence the total inductance is 5.5 mH

Answer 2

Explanation:

Given:

An inductor $2mh,3.3mh,0.2mh$ are connected in the series.

To find:

The total inductance of the inductor $2mh,3.3mh,0.2mh$.

Solution:

• The total inductance of the series chain can be calculated by simply adding together the individual inductances of the inductors in series just like adding together resistors in series.

• This approach is only possible where there is "No" mutual inductance or magnetic coupling between two or more of the inductors.
• In a series circuit, the total inductance$(L_{T})$ of any two or more inductors connected together in a series will always be greater than the value of the largest inductor in the series chain.

The formula for total inductance in series,

$L_{Total} =L_{1} +L_{2} +L_{3} +...L_{n}$

Given that, $L_{1} =2mh$

                  $L_{2}=3.3mh$      

                  $L_{3}=0.2mh$

   $L_{Total}=2+3.3+0.2$

∴ $L_{Total} =5.5mh$

Answer:

Hence, the total inductance is $5.5mh.$